re: #183 Killian Bundy

/okay, sorry, so a change in an acceleration rate doesn’t count?

When I post a formula for a change in an acceleration rate, it counts. So far, I haven’t put a post anywhere on LGF that discusses that, however.

In post #168, the example was for a single change in velocity (only one acceleration rate):

Formula for velocity? Δv = v₂ - v₁

So, the two translations I posted below are correct:

In plain English: “The change in velocity is equal to the second velocity measurement minus the first velocity measurement.”

In “mathspeak”: “Delta v equals v-sub-2 minus v-sub-1.”