re: #415 LudwigVanQuixote

Might what? Depending on how you mean that, you are either wrong or on the way to the answer!

Well, let’s say a couple has three daughters then one boy and so they have to stop. Three other couples could have had one boy at the same time of that happening.
Prob. of first parents having 3 daughters in a row: (.5)*(.5)*(.5) = .125
Prob. of three separate parents having three sons and not one of the couples having a daughter: same.
Correct?